# ABCD is a

Given that,

ABCD is a cyclic trapezium with AD BC and B = 70o

Then,

B + D = 180o

70o + D = 180o

D = 110o

Then,

A + B = 180o (Co. interior angle)

A + 70o = 180o

A = 110o

Since, ABCD is a cyclic quadrilateral

Then, A + C = 180o

110o + C = 180o

C = 70o

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