Q. 1 C

Find the nature of the roots of the following quadratic equations:

5x2 – 4x + 1 = 0

Answer :

Given: 5x2 – 4x + 1 = 0

Comparing with standard quadratic equation ax2 + bx + c = 0


a = 5, b = – 4, c = 1


Discriminant D = b2 – 4ac


= (– 4)2 – 4.5.1


= 16 – 20 = – 4 < 0


Hence the equation has no real roots.


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