Answer :

Given: x2 – 2ax + (a2 – b2) = 0

Comparing with standard quadratic equation Ax2 + Bx + C = 0


A = 1, B = – 2a, C = a2 – b2


Discriminant D = B2 – 4AC


= (– 2a)2 – 4.1.(a2 – b2)


= 4a2 – 4a2 + 4 b2 = 4 b2 > 0


Hence the roots of equation are real.



Roots are given by




x = (a + b) or x = (a – b)


Hence the roots of equation are (a + b) or (a – b)


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