Q. 264.5( 4 Votes )

Find the roots of each of the following equations, if they exist, by applying the quadratic formula:

x2 – 2ax + (a2 – b2) = 0

Answer :

Given: x2 – 2ax + (a2 – b2) = 0

Comparing with standard quadratic equation Ax2 + Bx + C = 0


A = 1, B = – 2a, C = a2 – b2


Discriminant D = B2 – 4AC


= (– 2a)2 – 4.1.(a2 – b2)


= 4a2 – 4a2 + 4 b2 = 4 b2 > 0


Hence the roots of equation are real.



Roots are given by




x = (a + b) or x = (a – b)


Hence the roots of equation are (a + b) or (a – b)


Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Related Videos
Get To Know About Quadratic Formula42 mins
Quiz | Knowing the Nature of Roots44 mins
Take a Dip Into Quadratic graphs32 mins
Foundation | Practice Important Questions for Foundation54 mins
Nature of Roots of Quadratic Equations51 mins
Getting Familiar with Nature of Roots of Quadratic Equations51 mins
Quadratic Equation: Previous Year NTSE Questions32 mins
Champ Quiz | Quadratic Equation33 mins
Understand The Concept of Quadratic Equation45 mins
Quiz | Lets Solve Imp. Qs of Quadratic Equation43 mins
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
view all courses