Q. 644.4( 8 Votes )

Solve each of the following quadratic equations:


Answer :

Given:

taking LCM



(3x + 4)(x + 4) = 5x2 + 15x + 10 cross multiplying


3x2 + 16x + 16 = 5x2 + 15x + 10


2x2 - x - 6 = 0


Using the splitting middle term - the middle term of the general equation is divided in two such values that:


Product = a.c


For the given equation a = 2 b = - 1 c = - 6


= 2. - 6 = - 12


And either of their sum or difference = b


= - 1


Thus the two terms are - 4 and 3


Difference = - 4 + 3 = - 1


Product = - 4.3 = 12


2x2 - x - 6 = 0


2x2 - 4x + 3x - 6 = 0


2x(x - 2) + 3(x - 2) = 0


(x - 2) (2x + 3) = 0


(x - 2) = 0 or (2x + 3) = 0



Hence the roots of equation are


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