Q. 554.5( 2 Votes )

x2 – 4ax + 4a2 – b2 = 0

Answer :

Using splitting middle term, the middle term of the general equation is divided in two such values that:

Product = a.c

For the given equation

= =

And either of their sum or difference = b


Thus the two terms are

Sum =



Product = using

= =

x[x-(2a + b)]-(2a-b)[x-(2a + b)] = 0

[x-(2a-b)][x-(2a + b)] = 0

[x-(2a-b)] = 0 or [x-(2a + b)] = 0

x = (2a-b) or x = (2a + b)

Hence roots of equation are x = (2a - b) or x = (2a + b)

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Related Videos
Get To Know About Quadratic Formula42 mins
Quiz | Knowing the Nature of Roots44 mins
Take a Dip Into Quadratic graphs32 mins
Foundation | Practice Important Questions for Foundation54 mins
Nature of Roots of Quadratic Equations51 mins
Getting Familiar with Nature of Roots of Quadratic Equations51 mins
Quadratic Equation: Previous Year NTSE Questions32 mins
Champ Quiz | Quadratic Equation33 mins
Understand The Concept of Quadratic Equation45 mins
Balance the Chemical Equations49 mins
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
view all courses