Q. 33.6( 18 Votes )

Show that the roots of the equation x2 + px – q2 = 0 are real for all real values of p and q.

Answer :

Given equation x2 + px – q2 = 0

a = 1 b = p x = – q2


Discriminant D = b2 – 4ac


= (p)2 – 4.1. – q2


= (p2 + 4q2) > 0


Thus the roots of equation are real.


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