Q. 263.5( 2 Votes )

If the equation x2 - kx + 1 = 0 has no real roots then
A. k < - 2

B. k > 2

C. - 2 < k < 2

D. none of these

Answer :

Given the equation x2 - kx + 1 = 0 has no real roots


a = 1 b = - k c = 1


Thus D = b2 - 4ac < 0


( - k)2 - 4.1.1 < 0


k2 - 4 < 0


k2 < 4


- 2 < k < 2

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