Q. 463.9( 8 Votes )

Solve each of the following quadratic equations:

abx2 + (b2 - ac)x - bc = 0

Answer :

abx2 + (b2 - ac)x - bc = 0

abx2 + (b2 - ac)x - bc = 0

abx2 + b2x - acx - bc = 0

bx (ax + b) - c (ax + b) = 0 taking bx common from first two terms and –c from last two

(ax + b) (bx - c) = 0

(ax + b) = 0 or (bx - c) = 0

Hence the roots of equation are

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