Q. 624.9( 9 Votes )

Solve each of the following quadratic equations:


Answer :

Given:

taking LCM




cross multiplying


3x2 - 15x + 15 = 5x2 - 30x + 40


2x2 - 15x + 25 = 0


Using the splitting middle term - the middle term of the general equation is divided in two such values that:


Product = a.c


For the given equation a = 2 b = - 15 c = 25


= 2.25 = 50


And either of their sum or difference = b


= - 15


Thus the two terms are - 10 and - 5


Sum = - 10 - 5 = - 15


Product = - 10. - 5 = 50


2x2 - 15x + 25 = 0


2x2 - 10x - 5x + 25 = 0


2x(x - 5) - 5(x - 5) = 0


(x - 5)(2x - 5) = 0


(x - 5) = 0 or (2x - 5) = 0



Hence the roots of equation are


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