Q. 235.0( 5 Votes )

Solve each of the following quadratic equations:

3√7x2 + 4x – √7 = 0

Answer :


Using the splitting middle term - the middle term of the general equation is divided in two such values that:


Product = a.c


For the given equation a = 3√7 ;b = 4 ;c = -√7


= 3√7.-√7 = 3.-7 = -21


(using 7 = √7.√7)


And either of their sum or difference = b


= 4


Thus the two terms are 7 and - 3


Difference = 7 - 3 = 4


Product = 7× - 3 = - 21




( using 7 = √7.√7)



(√7 x-1)(3x + √7) = 0


(√7 x-1) = 0 or (3x + √7) = 0


x = 1/√7 or x = (-7)/√3


Roots of equation are


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