# Solve each of the following quadratic equations:15x2 - 28 = x  Using the splitting middle term - the middle term of the general equation is divided in two such values that:

Product = a.c

For the given equation a = 15 ; b = -1; c = -28

= 15. - 28 = - 420

And either of their sum or difference = b

= - 1

Thus the two terms are - 21 and 20

Difference = - 21 + 20 = - 1

Product = - 21.20 = - 420  3x(5x-7) + 4(5x-7) = 0

(5x-7)(3x + 4) = 0

(5x-7) = 0 or (3x + 4) = 0

x = 7/5 or x = (-4)/3

Roots of equation are 7/5, - 4/3

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Related Videos  Get To Know About Quadratic Formula42 mins  Quiz | Knowing the Nature of Roots44 mins  Take a Dip Into Quadratic graphs32 mins  Foundation | Practice Important Questions for Foundation54 mins  Nature of Roots of Quadratic Equations51 mins  Getting Familiar with Nature of Roots of Quadratic Equations51 mins  Quadratic Equation: Previous Year NTSE Questions32 mins  Champ Quiz | Quadratic Equation33 mins  Understand The Concept of Quadratic Equation45 mins  Quiz | Lets Solve Imp. Qs of Quadratic Equation43 mins
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation view all courses 