Q. 174.2( 6 Votes )

Solve each of the following quadratic equations:

15x2 - 28 = x

Answer :



Using the splitting middle term - the middle term of the general equation is divided in two such values that:


Product = a.c


For the given equation a = 15 ; b = -1; c = -28


= 15. - 28 = - 420


And either of their sum or difference = b


= - 1


Thus the two terms are - 21 and 20


Difference = - 21 + 20 = - 1


Product = - 21.20 = - 420




3x(5x-7) + 4(5x-7) = 0


(5x-7)(3x + 4) = 0


(5x-7) = 0 or (3x + 4) = 0


x = 7/5 or x = (-4)/3


Roots of equation are 7/5, - 4/3


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