# If the roots of the equations ax2 + 2bx + c = 0 and are simultaneously real then prove that b2 = ac.

Given the roots of the equations ax2 + 2bx + c = 0 are real.

Comparing with standard quadratic equation Ax2 + Bx + C = 0

A = a B = 2b C = c

Discriminant D1 = B2 – 4AC ≥ 0

= (2b)2 – 4.a.c ≥ 0

= 4(b2 –ac) ≥ 0

= (b2 –ac) ≥ 0 – – – – – (1)

For the equation Discriminant D2 = b2 – 4ac ≥ 0

= = 4(ac – b2) ≥0

= – 4(b2–ac) ≥0

= (b2 –ac) ≥0 – – – – – (2)

The roots of the are simultaneously real if (1) and (2) are true together

b2 –ac = 0

b2 = ac

Hence proved.

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