Q. 275.0( 1 Vote )

For what values of k, the equation kx2 - 6x - 2 = 0 has real roots?
A.

B.

C.

D. none of these

Answer :

Given the equation kx2 - 6x - 2 = 0 has real roots


a = k b = - 6 c = - 2


Thus D = b2 - 4ac ≥0


( - 6)2 - 4.k. - 2 ≥0


36 + 8k ≥0


8k≥ - 36


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