Answer :

Given: 4x2 + 4bx – (a2 – b2) = 0

Comparing with standard quadratic equation Ax2 + Bx + C = 0


A = 4, B = 4b, C = – (a2 – b2)


Discriminant D = B2 – 4AC


= (4b)2 – 4.4. – (a2 – b2)


= 16b2 + 16a2 – 16b2 = 16 a2 > 0


Hence the roots of equation are real.



Roots are given by





Hence the roots of equation are


Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
caricature
view all courses