# If the equation x2 + 5kx + 16 = 0 has no real roots thenA. k > 8/5B. k < –8/5C. –8/5 < k < 8/5D. none of these

Given the equation x2 + 5kx + 16 = 0 has no real

a = 1 b = 5k c = 16

Thus D = b2 - 4ac < 0

= (5k)2 - 4.1.16 < 0

= 25k2 - 64 < 0

25k2 = 64  Rate this question :

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