Q. 164.0( 9 Votes )

Find the values of p for which the quadratic equation 2x2 + px + 8 = 0 has real roots.

Answer :

Given that the quadratic equation 2x2 + px + 8 = 0 has real roots

Comparing with standard quadratic equation ax2 + bx + c = 0

a = 2 b = p c = 8

Thus D = 0

Discriminant D = b2 – 4ac≥0

(p)2 – 4.2.8≥0

(p)2 – 64≥0

p2 ≥ 64 taking square root on both sides

p≥8 or p≤ – 8

The roots of equation are real for p≥8 or p≤ – 8

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Related Videos
Get To Know About Quadratic Formula42 mins
Quiz | Knowing the Nature of Roots44 mins
Take a Dip Into Quadratic graphs32 mins
Foundation | Practice Important Questions for Foundation54 mins
Nature of Roots of Quadratic EquationsFREE Class
Getting Familiar with Nature of Roots of Quadratic Equations51 mins
Quadratic Equation: Previous Year NTSE Questions32 mins
Champ Quiz | Quadratic Equation33 mins
Balance the Chemical Equations49 mins
Champ Quiz | Quadratic Equation48 mins
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
view all courses