Given: 5x (x – 2) + 6 = 05x2 – 10x + 6 = 0Comparing with standard quadratic equation ax2 + bx + c = 0a = 5, b = – 10, c = 6Discriminant D = b2 – 4ac= (– 10)2 – 4.5.6= 100 – 120 = – 20 < 0Hence the equation has no real roots.

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RS Aggarwal - Mathematics

10. Quadratic Equations

1. Real Numbers
2. Polynomials
3. Linear Equations in Two Variables
Triangles
5. Trigonometric Ratios
6. T-Ratios of Some Particular Angles
7. Trigonometric Ratios of Complementary Angles
8. Trigonometric Identities
10. Quadratic Equations
9. Mean, Median, Mode of Grouped Data, Cumulative Frequency Graph and Ogive
11. Arithmetic Progression
12. Circles
13. Constructions
14. Heights and Distances
15. Probability
16. Coordinate Geometry
17. Perimeter and Area of Plane Figures
18. Area of Circle, Sector and Segment
19. Volume and Surface Area of Solids
20. Summative Assessment I
21. Summative Assessment II

Exercise 10A

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Exercise 10B

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Exercise 10C

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Exercise 10D

1 A 1 B 1 C 1 D 1 E 1 F 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22

Exercise 10E

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Exercise 10F

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Q. 1 D5.0( 1 Vote )

Find the nature o

Class 10th RS Aggarwal - Mathematics 10. Quadratic Equations

Answer :

Given: 5x (x – 2) + 6 = 0

5x² – 10x + 6 = 0

Comparing with standard quadratic equation ax² + bx + c = 0

a = 5, b = – 10, c = 6

Discriminant D = b² – 4ac

= (– 10)² – 4.5.6

= 100 – 120 = – 20 < 0

Hence the equation has no real roots.

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