Q. 275.0( 5 Votes )

Solve each of the following quadratic equations:

√3x2 – 2√2x – 2√3 = 0

Answer :


Using the splitting middle term - the middle term of the general equation is divided in two such values that:


Product = a.c


For the given equation a = √3 b = -2√2 c = -2√3


= √3.-2√3 = -2.3 = -6


And either of their sum or difference = b


= -2√2


Thus the two terms are -3√2 and √2


Difference = -3√2 + √2 = -2√2


Product = -3√2 × √2 = -3.2 = -6




(On using3√2 = √3 √3 √2 = √3.√6)



(2√3 = √2 √2 √3 = √2.√6)




Roots of equation are


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