Answer :

Given: x2 + 6x – (a2 + b2 – 8) = 0

Comparing with standard quadratic equation Ax2 + Bx + C = 0


A = 1, B = 6, C = – (a2 + b2 – 8)


Discriminant D = B2 – 4AC


= (6)2 – 4.1. – (a2 + b2 – 8)


= 36+ 4a2 + 8a – 32 = 4a2 + 8a + 4


= 4(a2 + 2a + 1)


= 4(a + 1)2 > 0 Using a2 + 2ab + b2 = (a + b)2


Hence the roots of equation are real.



= 2(a + 1)


Roots are given by




x = (a – 2) or x = – (4 + a)


Hence the roots of equation are (a – 2) or – (4 + a)


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