Answer :

Given: x2 – 4ax – b2 + 4a2 = 0

Comparing with standard quadratic equation Ax2 + Bx + C = 0


A = 1, B = – 4a, C = – b2 + 4a2


Discriminant D = B2 – 4AC


= (– 4a)2– 4.1. (– b2 + 4a2)


= 16a2 + 4b2 – 16a2 = 4 b2 > 0


Hence the roots of equation are real.



Roots are given by




x = (2a – b) or x = (2a + b)


Hence the roots of equation are (2a – b) or (2a + b)


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