Q. 245.0( 5 Votes )

Solve each of the following quadratic equations:

√7x2 – 6x – 13√7 = 0

Answer :


Using the splitting middle term - the middle term of the general equation is divided in two such values that:


Product = a.c


For the given equation


= √7.-13√7 = -13.7 = -91


And either of their sum or difference = b


= - 6


Thus the two terms are 7 and - 13


Difference = - 13 + 7 = - 6


Product = 7. - 13 = - 91





x(√7 x-13) + √7 (√7 x-13) = 0


(x + √7)(√7 x-13) = 0


(x + √7) = 0 or (√7 x-13) = 0


x = -√7 or x = 13/√7


Roots of equation are


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