Q. 563.7( 18 Votes )

Solve each of the following quadratic equations:


Answer :



taking LCM



4x2 + 4ax + 2bx = - 2ab cross multiplying


4x2 + 4ax + 2bx + 2ab = 0


4x(x + a) + 2b(x + a) = 0 taking 4x common from first two terms and 2b from last two


(x + a) (4x + 2b) = 0


(x + a) = 0 or (4x + 2b) = 0



Hence the roots of equation are


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