Q. 54.2( 5 Votes )

Solve each of the following quadratic equations:

(2x-3) (3x + 1) = 0

Answer :

(2x-3) (3x + 1) = 0


2x(3x + 1)-3(3x + 1) = 0 taking common from first two terms and last two terms


(2x-3)(3x + 1) = 0


(2x-3) = 0 or (3x + 1) = 0


x = 3/2 or x = (-1)/3


Roots of equation are 3/2, (-1)/3


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