Answer :
Let the required natural numbers x and (x + 3)
x < x + 3
Thus
According to given condition,
taking LCM
cross multiplying
Using the splitting middle term – the middle term of the general equation is divided in two such values that:
Product = a.c
For the given equation a = 1 b = 3 c = – 28
= 1. – 28 = – 28
And either of their sum or difference = b
= 3
Thus the two terms are 7 and – 4
Difference = 7 – 4 = 3
Product = 7. – 4 = – 28
x(x + 7) – 4(x + 7) = 0
(x – 4) (x + 7) = 0
(x – 4) = 0 or (x + 7) = 0
x = 4 or x = – 7
x = 4 (x < x + 3)
x + 3 = 4 + 3 = 7
Hence required numbers are 4 and 7.
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