A particle A havi

Given:
Charge of the particle A and B: q₁=q₂= q = 2.0 × 10^–6 C.
Mass of the particles A and B : m = 100 g =0.1 kg.
Inclination of the inclined plain : θ = 30°

Formula used:
The particle A and B will exert electrostatic repulsive forces on each other.
This can be given by Coulomb’s Law:
We use Coulomb’s law:
Where F_e is the electrostatic force on b due to A, k is a constant .
k = = 9× 10⁹ Nm²C^-2 and r is the distance between two charges.
Particle B would face a friction force opposite to the rolling force due to inclination. It is given as:
F= mgsinθ
For particle B to remain in equilibrium with the inclination and particle A. The electrostatic force of repulsion and the friction force must be equal.
F_e = F




Hence, particle b must be place at a distance of 0.2701m from particle A to remain in equilibrium.