# Two charges 2.0 × 10–6 C and 1.0 × 10–6 C are placed at a separation of 10 cm. Where should a third charge be placed such that it experiences no net force due to these charges?

Given:

Charges:

Distance between the charge is 10 cm

Let the third charge be q. There are three possible scenarios:

As we can see from the picture, the only possible location for q where net force on q is zero is between the two charges. Let it be x m away from q1, x > 0.

________________________________________________

Formula used:

By Coulomb’s law, the electric force is given by:

Where ϵ0 is the permittivity of free space

k is the electrostatic constant

q1 and q2 are the magnitude of charges

r is the distance of separation between the charges

__________________________________________________

Force on q due to q1 is given by:

Force on q due to q2 is given by:

Now,

As x > 0. The correct option is 0.041.

Distance from charge q2 = 0.1 – 0.041 = 0.059 m

Hence, the charge q should be placed 5.9 cm from q2.

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Related Videos
Superfast Revision of Potential & Potenial Energy (Theory + Interactive Quiz)47 mins
Check your knowledge of Electric Potential | Quiz45 mins
Relation between electric field and potential34 mins
Relation between Electric field & Potential45 mins
Interactive quiz on Relation between electric field and potential43 mins
Electric field inside cavity37 mins
Few Applications of Gauss's law54 mins
Test Your Knowledge of Electric Charge & Coulomb's Law47 mins
Electric potential inside solid and hollow sphere30 mins
Electric Field Lecture47 mins
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
view all courses