Q. 14.6( 20 Votes )

Figure shows some of the electric field lines corresponding to an electric field. The figure suggests that



A. EA > EB > EC

B. EA = EB = EC

C. EA = EC > EB

D. EA = EC < EB

Answer :

At any given point in the electric field region, the electric flux (i.e. the number of field lines per unit area) determines the intensity of the field. The points in the region where the flux is more are associated with strong electric fields.


For a given area, field lines are dense and equal in number at point A and C.


Therefore, EA = EC


And at point B, the field lines are far away which indicates lesser intensity of electric field at point B than at point A and C.

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Related Videos
Superfast Revision of Potential & Potenial Energy (Theory + Interactive Quiz)47 mins
Check your knowledge of Electric Potential | Quiz45 mins
Relation between electric field and potential34 mins
Relation between Electric field & Potential45 mins
Interactive quiz on Relation between electric field and potential43 mins
Electric field inside cavity37 mins
Few Applications of Gauss's law54 mins
Test Your Knowledge of Electric Charge & Coulomb's Law47 mins
Electric potential inside solid and hollow sphere30 mins
Electric Field Lecture47 mins
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
view all courses
RELATED QUESTIONS :