# Assume that each

Given:
Atomic weight of copper = 64 g mol-1
Mass of copper wire : m = 6.4 g
Formula used:
We know that,
Number of moles in 64 g of copper = 1
Thus, number of moles in 6.4 g of copper = 0.1
Also,
Number of atoms in one mole=NA
Here, NA is the Avogadro Number : NA = 6.023× 1023 atoms
No.of atoms in 0.1 mole of copper=0.1× 6.023× 1023
No.of atoms in 0.1 mole of copper=0.1× 6.023× 1022
It is given that each atom contributes one free electron,
Therefore in 0.1 mole of copper
will contribute
Hence, there will be
free electron in 6.4 g of copper.

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