# An electric field

Given:
Magnitude of the electric field : E = 1000 NC–1
Separation between the plates: r = 2 cm = 0.02 m
Angle made by the projection with the field : θ = 60° Formula used:
(a)
The Potential difference is:
V = -E.r
Here, E is the electric field and r is the separation between the plates.
V = - 1000 × 0.2
V = -200 = |-200| = 200 V

Hence, the potential difference between the plates is of 200 V
(b)
Charge on an electron: e = -1.6× 10-19 C
We know that
F=qE=ma
Where F is the electric force, E is the electric field, m is the mass of the body and a is the acceleration of the body.
Here, q=e of electron. And m = 9.7× 10-31 kg mass of the electron.  Using one of the equations of motion we get,
v2=u2+2as

Here, v is the final velocity of the electron= 0
Here v is zero as it we have to calculate u when it just reaches the upper plate, u is the initial velocity of the electron, s is the distance between the plates: s=r and a is the acceleration of the electrons    Hence, with a minimum speed of 2.64× 106 m/s2 should the electron be projected from the lower plate in the direction of the field for it to reach the upper plate.
(c)
As direction of projection makes an angle 60° with the electric field.
Initial velocity is resolved into its cos component which is along the direction of the electric field as shown in the figure above.
Hence, u’=ucos(60° ), u’ is the resolved initial velocity.
Using the same equation of motion used in (b) we get, Where h is the maximum height reached by the electron.   Hence, the maximum height reached by the electron is 4.7× 10-3 m.

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation view all courses RELATED QUESTIONS :

(a) In a quark moPhysics - Exemplar

A uniform field oHC Verma - Concepts of Physics Part 2

The work done to Physics - Exemplar

A uniform electriHC Verma - Concepts of Physics Part 2

Equipotential surPhysics - Exemplar

If a conductor haPhysics - Exemplar

Two charges q<subPhysics - Exemplar

Two charges –q eaPhysics - Exemplar

Two point chargesPhysics - Exemplar

Calculate potentiPhysics - Exemplar