Q. 34

The electric force experienced by a charge of 1.0 × 10–6 C is 1.5 × 10–3 N. Find the magnitude of the electric field at the position of the charge.

Answer :


Given:
Electric Force exerted by a charge: F = 1.5 × 10–3 N
Charge: q = 1.0 × 10–6 C
Formula used:
Here we use:
Where, F is the electric force, q is the charge and E is the electric field at the position of the charge.
Substituting we get,



Hence, the magnitude electric field at the position of the charge is 1.5× 103 N/C


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