# Two particles A a

Given:
Charge on particles A and B: q1= q2= Q
Separation between A and B : d here ‘x’ is the distance at which particle C of charge ‘q’ is place on the perpendicular bisector of AB.
Formula used:
From the figure we can find sinθ : The horizontal components of force cancel each other.
Total vertical component of force is: F’= 2Fsinθ
We use Coulomb’s Law: Where F is the electrostatic force on b due to A, k is a constant .
k = = 9× 109 Nm2C-2 and r is the distance between the two charges.
Here r = Substituting we get,             The magnitude of maximum Force is: Hence, the particle C must be placed at a distance of from the perpendicular bisector of AB so as to experience a maximum force of magnitude Rate this question :

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