Q. 313.7( 9 Votes )

# Two particles A a

Answer :

**Given:**Charge on particles A and B: q

_{1}= q

_{2}= Q

Separation between A and B : d

here ‘x’ is the distance at which particle C of charge ‘q’ is place on the perpendicular bisector of AB.

**Formula used:**

From the figure we can find sinθ :

The horizontal components of force cancel each other.

Total vertical component of force is: F’= 2Fsinθ

We use Coulomb’s Law:

Where F is the electrostatic force on b due to A, k is a constant .

k = = 9× 10

^{9}Nm

^{2}C

^{-2}and r is the distance between the two charges.

Here r =

Substituting we get,

The magnitude of maximum Force is:

Hence, the particle C must be placed at a distance of from the perpendicular bisector of AB so as to experience a maximum force of magnitude

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