Answer :


Given:
Charge of particles A and B : q = Q
Separation between A and B : d
(a)

here ‘x’ is the distance at which particle C of mass m and charge ‘q’ is place on the perpendicular bisector of AB.
Formula used:
From the figure we can find sinθ :
The horizontal components of force cancel each other.
Total vertical component of force is: F’= 2Fsinθ
We use Coulomb’s Law:
Where F is the electrostatic force on b due to A, k is a constant .
k =
= 9× 109 Nm2C-2 and r is the distance between the two charges.
Here r =

Substituting we get,

F’ is the net electric force experience by particle C of charge q.
(b)
When x
d,
Thus, x2 can be neglected.
Substituting we get,


Thus, force is proportional to x.
(c)
The condition for Simple harmonic Motion of a particle is:
Here, m is the mass of the particle C, ω is the angular frequency.
Thus comparing two equations of F’, we get
We know that Where t is the Time Period.




Hence time period when the particle is released after a small displacement under SHM is


Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
caricature
view all courses
RELATED QUESTIONS :

(a) Describe briePhysics - Board Papers

Repeat the previoHC Verma - Concepts of Physics Part 2

There is another Physics - Exemplar

Does the charge gPhysics - Board Papers