Q. 413.6( 9 Votes )
A 10 cm long rod
Length of the rod : L = 10cm = 0.1m
Charge on the rod; q = +50 μC= 50× 10-6 C
Here, C is 10 cm = 0.1 m away from both ends of the rod AB.
Distance between C and centre of AB : r
From Pythagoras Theorem,
∴ r2= [0.1]2- [0.05]2
∴ r2= 7.5×10-3
Now we know that, Electric field at a point on the perpendicular bisector of a uniformly charged rod is:
Here, k is a constant and k= =9× 109 Nm2C-2 . q is the point charge, L is the length of the rod and Q is the magnitude of the charge.
Substituting we get,
Hence, electric field at a point 10 cm away from the ends of the rod is 5.2 × 107 NC-1.
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