# Repeat the previous problem if the particle is displaced through a distance x along the line AB.

Given:
Charge of particles A and B : q = Q
Separation between A and B : d Here x is the displacement of particle C along AB.
Distance between A and C is : Distance between B and C is : Formula used:
For part (a), we will be using Coulomb’s Law, Where F is the electrostatic force on B due to A, k is a constant .
k = = 9× 109 Nm2C-2 and r is the distance between the two charges.
q1=q2=Q.
now, the net force acting on C is:      Fnet is the net electric force experience by particle C of charge q.
(b)
When x
d,
x2
(d/2)2
Thus x2 can be neglected.
We get,  Fnet α x

Thus, when xd force is proportional to x

(c)
The condition for Simple harmonic Motion of a particle is:
F'=mω2x
Here, m is the mass of the particle C, ω is the angular frequency.
Let Fnet = F’
Thus comparing two equations of F’, we get We know that Where t is the Time Period.   Hence time period when particle is displaced along AB is Rate this question :

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