# A pendulum bob of

Given:
Mass of the bob: m = 80 mg= 80× 10-6 kg
Charge on the bob: q = 2 × 10–8 C
Electric field : E = 20 kVm–1 = 20× 103 Vm-1. Here the electric field is horizontal.
The tension in the string is resolved into two components:
Horizontal component : Tsinθ
Vertical component : Tcosθ
As shown in the figure.
Formula Used:
Since electric field acts on the bob having charge q, it experiences an electric field in horizontal direction.
Electric force is given as:
F=qE
F is electric force, q is the charge on the bob and E is the horizontal electric field. This electric force is balanced by the horizontal component of the tension.
Tsinθ = qE
Now the vertical component of tension is balanced by the weight of the bob.
Tcosθ=mg
Dividing we get,     Substituting the value of θ , we can calculate tension in the string.   Hence the tension in the string is 8.8×10-4 N.

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation view all courses RELATED QUESTIONS :

Five charges, q ePhysics - Exemplar

Fig. 1.10 represePhysics - Exemplar

The electric forcHC Verma - Concepts of Physics Part 2

A particle of masHC Verma - Concepts of Physics Part 2

The bob of a simpHC Verma - Concepts of Physics Part 2

A positive chargeHC Verma - Concepts of Physics Part 2

A rod of length LHC Verma - Concepts of Physics Part 2

Consider a uniforHC Verma - Concepts of Physics Part 2