Q. 434.0( 3 Votes )
A wire is bent in
Uniformly distributed Charge on the regular hexagon : q
When a wire is bent in the form of a regular hexagon having charge q uniformly distributed, each point on the hexagon will contribute same magnitude of electric field.
Say, 6 vertices of the hexagon have same charge q.
Thus they will produce same electric field E at the center.
This electric field gets nullified as same magnitude is acting from both sides.
Electric field at a point due to a point charge is given as:
Where k is a constant and k= =9× 109 Nm2C-2. q is the charge and r is the distance between the point and the charge.
From the figure E1 is the electric field due to vertex 1 at the center and E2 is the electric field due to vertex 2 at the center diametrically opposite to vertex 1.
Thus net electric field at center due to 1 and 2 is
Enet = E1-E2
∴ Enet = 0
Eventually electric field due to all 6 vertices cancel out each other at the center.
Hence, electric field at the center of the regular hexagon is zero.
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