Q. 44.4( 8 Votes )

Two equal charges are placed at a separation of 1.0 m. What should be the magnitude of the charges so that the force between them equals the weight of a 50 kg person?

Answer :

Given:


Mass of the person


Weight of the person,


Let the magnitude of charge on both be q.


Here,


Distance of separation,


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Formula used:


By Coulomb’s law, the electric force is given by:



Where ϵ0 is the permittivity of free space


k is the electrostatic constant


q1 and q2 are the magnitude of charges


r is the distance of separation between the charges


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Rearranging, we get



Substituting the corresponding values, we get




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