Q. 44.4( 8 Votes )
Two equal charges are placed at a separation of 1.0 m. What should be the magnitude of the charges so that the force between them equals the weight of a 50 kg person?
Mass of the person
Weight of the person,
Let the magnitude of charge on both be q.
Distance of separation,
By Coulomb’s law, the electric force is given by:
Where ϵ0 is the permittivity of free space
k is the electrostatic constant
q1 and q2 are the magnitude of charges
r is the distance of separation between the charges
Rearranging, we get
Substituting the corresponding values, we get
Rate this question :
charges q and –3q are placed fixed on x-axis separated by distance ‘d’. Where should a third charge 2q be placed such that it will not experience any force?Physics - Exemplar
NaCl molecule is bound due to the electric force between the sodium and the chlorine ions when one electron of sodium is transferred to chlorine. Taking the separation between the ions to be 2.75 × 10–8 cm, find the force of attraction between them. State the assumptions (if any) that you have made.HC Verma - Concepts of Physics Part 2