Q. 35

# Two particles A a

Answer :

**Given:**Charge on particle A: q

_{A}= +2× 10

^{-6}C

Charge on particle B : q

_{B}= -4× 10

^{-6}C

Separation between A and B : r = 20.0 cm=0.2m

**Formula used:**

Electric Field given as:

Here, k is a constant and k= =9× 10

^{9}Nm

^{2}C

^{-2}. q is the point charge and r is the distance between two charges.

Also,

Electric potential is given as:

Here, k is a constant and k= =9× 10

^{9}Nm

^{2}C

^{-2}.q is the point charge and r is the distance between two charges.

Now,

Let there be a point at distance ‘x’ from A where net electric field is zero.

Distance between A and the point be : r

_{A}= x m

Distance between B and the point be : r

_{B}= (0.2-x) m

Hence, electric field is zero at a point 0.4825 m from A along AB.

Now,

Zero Net potential at the point is

OR

Hence, potential can be zero at 0.0666 m from A along AB and at 0.2 m from B along AB.

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