# A uniform electric field of 10 N C–1 exists in the vertically downward direction. Find the increase in the electric potential as one goes up through a height of 50 cm.

Given:
Electric field: E= 10 N C–1
Change in Height : dh = 50 cm= 0.5 m
Formula used:
Since the electric field exists in vertically downward direction, E becomes negative as one goes up. E= -10 N C–1
Change in potential is :
dV = -E.dr
Here, dV is change in potential, dr is the distance moved and E is the electric field.
In this case dr=dh
dV = -(-10)× 0.5
dV = 5 V
Hence, Increase in potential as one goes up by 50cm is 5V.

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