Q. 424.0( 8 Votes )

Consider a uniformly charged ring of radius R. Find the point on the axis where the electric filed is maximum.

Answer :

Charge of the ring: Q
Radius of the ring :R
Let P be the point where electric field is found.
Distance between center of the ring and P is x.

Formula used:
We know that electric field at any point on the axis at a distance x from the center is:
Where k is a constant and k= =9× 109 Nm2C-2. Q is the charge of the ring, x is the distance between center of the ring and point P and R is the radius of the ring.
Now for the electric field to be maximum, we use the maxima property:
Taking derivative of E w.r.t x,

Hence Electric field is maximum at on the axis.

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