Q. 424.0( 8 Votes )

# Consider a unifor

Given:
Charge of the ring: Q
Radius of the ring :R
Let P be the point where electric field is found.
Distance between center of the ring and P is x. Formula used:
We know that electric field at any point on the axis at a distance x from the center is: Where k is a constant and k= =9× 109 Nm2C-2. Q is the charge of the ring, x is the distance between center of the ring and point P and R is the radius of the ring.
Now for the electric field to be maximum, we use the maxima property: Taking derivative of E w.r.t x,       Hence Electric field is maximum at on the axis.

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