Q. 424.0( 8 Votes )

# Consider a unifor

Answer :

**Given:**Charge of the ring: Q

Radius of the ring :R

Let P be the point where electric field is found.

Distance between center of the ring and P is x.

**Formula used:**

We know that electric field at any point on the axis at a distance x from the center is:

Where k is a constant and k= =9× 10

^{9}Nm

^{2}C

^{-2}. Q is the charge of the ring, x is the distance between center of the ring and point P and R is the radius of the ring.

Now for the electric field to be maximum, we use the maxima property:

Taking derivative of E w.r.t x,

Hence Electric field is maximum at on the axis.

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