Q. 163.5( 6 Votes )

Three equal charges, 2.0 × 10–6 C each, are held fixed at the three corners of an equilateral triangle of side 5 cm. Find the Coulomb force experienced by one of the charges due to the rest two.

Answer :


Let the force due to charge at corner B, C be FB, FC.

Charge at each corner, .

Note that the length of side of the triangle is.


Formula used:

By Coulomb’s law, the electric force is given by:

Where ϵ0 is the permittivity of free space

k is the electrostatic constant

q1 and q2 are the magnitude of charges

r is the distance of separation between the charges


Putting the values in the above formula, we get

We can see from the diagram that FCand FBcab be resolved into theirs x and y components.

The y’s are in the same direction and add up but the x’s are in the opposite direction, hence they cancel out.


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