Three equal charg
Let the force due to charge at corner B, C be FB, FC.
Charge at each corner, .
Note that the length of side of the triangle is.
By Coulomb’s law, the electric force is given by:
Where ϵ0 is the permittivity of free space
k is the electrostatic constant
q1 and q2 are the magnitude of charges
r is the distance of separation between the charges
Putting the values in the above formula, we get
We can see from the diagram that FCand FBcab be resolved into theirs x and y components.
The y’s are in the same direction and add up but the x’s are in the opposite direction, hence they cancel out.
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