Q. 104.3( 7 Votes )

Suppose all the electrons of 100g water are lumped together to form a negatively charged particle and all the nuclei are lumped together to form a positively charged particle. If these two particles are placed 10.0 cm away from each other, find the force of attraction between them. Compare it with your weight.

Answer :

Given:


Mass of water ,


Molar mass of water


Moles of water in 100g of water =


Number of electrons in 1 molecule of water = 2 times one electron each in hydrogen atom + 8 electrons in oxygen atom = 10 electrons


__________________________________________________


Formulas used:


The relation between molar mass M, mass of sample m and number of moles of sample n is given by:



1 mol of “something” contains NA number of “something”.


__________________________________________________


Number of electrons in 1 mol of electrons =


Number of electrons in 100 g of water





Negative charge on one electron =


Total negative charge


We have,


Charges:


Distance of separation,


________________________________________________


Formula used:


By Coulomb’s law, the electric force is given by:



Where ϵ0 is the permittivity of free space


k is the electrostatic constant


q1 and q2 are the magnitude of charges


r is the distance of separation between the charges


__________________________________________________


The magnitude of electric force is:





Let my mass m be 70 kg.




The electric force between the two charges is about 1022 times my weight!


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