Q. 135.0( 1 Vote )
An AP 5, 12, 19, ... has 50 terms. Its last term is
A. 343
B. 353
C. 348
D. 362
Answer :
Here, first term = 5
Common difference = 12 - 5 = 7
Given that there are 50 terms in the AP.
To find: Last term, i.e. 50th term = a50
Since an = a + (n - 1)d
∴ a50 = 5 + (50 - 1)7
= 5 + (49) × 7
= 5 + 343
= 348
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