Q. 84.4( 10 Votes )

How many terms are there in the AP 41, 38, 35, ..., 8?

Answer :

In the given AP, the first term = a =41

Common difference = d = 38 - 41 = - 3


Last term = 8


To find: No. of terms in the AP.


Since, we know that


an = a + (n - 1) × d


8 = 41 + (n - 1) × (-3)


8 - 41 = - 3n + 3


- 33 = - 3n + 3


- 33 - 3 = - 3n


- 3n = - 36


n = 36/3


n = 12


Number of terms = 12.


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