Answer :
Given: 4 × a4 = 18 × a18
To find : a22
Consider 4 × a4 = 18 × a18
⇒ 4 [a + (4 - 1)d] = 18 [a + (18 - 1)d]
⇒ 4a + 12d = 18a + 306d
⇒ - 14 a = 294 d
⇒ a = - 21d ………………(1)
Now, a22 = a + (22 - 1)d
⇒ a22 = a + 21d
⇒ a22 = - 21d + 21d (from equation 1)
⇒ a22 = 0
∴ a22 = 0
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