Q. 324.8( 15 Votes )

If 4 times the 4th term of an AP is equal to 18 times its 18th term then find its 22nd term.

Answer :

Given: 4 × a4 = 18 × a18

To find : a22


Consider 4 × a4 = 18 × a18


4 [a + (4 - 1)d] = 18 [a + (18 - 1)d]


4a + 12d = 18a + 306d


- 14 a = 294 d


a = - 21d ………………(1)


Now, a22 = a + (22 - 1)d


a22 = a + 21d


a22 = - 21d + 21d (from equation 1)


a22 = 0


a22 = 0


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