# If 4 times the 4th term of an AP is equal to 18 times its 18th term then find its 22nd term.

Given: 4 × a4 = 18 × a18

To find : a22

Consider 4 × a4 = 18 × a18

4 [a + (4 - 1)d] = 18 [a + (18 - 1)d]

4a + 12d = 18a + 306d

- 14 a = 294 d

a = - 21d ………………(1)

Now, a22 = a + (22 - 1)d

a22 = a + 21d

a22 = - 21d + 21d (from equation 1)

a22 = 0

a22 = 0

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