Q. 8

# Divide 24 in three parts such that they are in AP and their product is 440.

Let 24 be divided in numbers which are in AP as (a - d), a, (a + d).

Now, sum of the numbers = 24

(a - d) + a + (a + d) = 24

3a = 24

a = 8

Now, product of the numbers = 440

(a - d) × a × (a + d) = 440

Put the value of a, we get,

512 - 8d2 = 440

8d2 = 512 - 440 = 72

d2 = 9

d = � 3

If d = 3, then the numbers are 5, 8, 11.

If d = - 3, then the numbers are 11, 8, 5.

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