Q. 184.8( 8 Votes )

Find the sum of first 100 even natural numbers which are divisible by 5.

Answer :

First 100 even natural numbers which are divisible by 5 are 10, 20, 30, …, 1000

Here, first term = a = 10


Common difference = d = 10


Number of terms = 100


Now, Sum of n terms of this arithmetic series is given by:


Sn = [2a + (n - 1)d]


Therefore sum of 100 terms of this arithmetic series is given by:


S100 = [2(10) + (100 - 1)(10)]


= 50 × [20 + 990]


= 50 × 1010


= 50500


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