Q. 1 B4.3( 6 Votes )

Find the sum of each of the following APs:

9, 7, 5, 3, ... to 14 terms.

Answer :

Here, first term = 9

Common difference = 7 - 9 = - 2


Sum of first n terms of an AP is


Sn = [2a + (n - 1)d]


S14 = [2(9) + (14 - 1)(-2)]


= (7)(18 - 26)


= (7) × (-8)


= - 56


Thus, sum of 14 terms of this AP is - 56.


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