The 2nd term of an AP is 13 and its 5th term is 25. What is its 17th term?A. 69B. 73C. 77D. 81

Given: a2 = 13

a5 = 25

To find: a17

Consider a2 = 13

a + d = 13 …………….(1)

Consider a5 = 25

a + 4d = 25 …………….(2)

Subtracting equation (1) from equation (2), we get,

3d = 12

d = 4

Common difference = 4

From equation (1), we get

a = 13 - d

= 13 - 4

= 9

Thus a17 = a + 16d

= 9 + 16(4)

= 73

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