Q. 275.0( 5 Votes )

The 2nd term of an AP is 13 and its 5th term is 25. What is its 17th term?
A. 69

B. 73

C. 77

D. 81

Answer :

Given: a2 = 13


a5 = 25


To find: a17


Consider a2 = 13


a + d = 13 …………….(1)


Consider a5 = 25


a + 4d = 25 …………….(2)


Subtracting equation (1) from equation (2), we get,


3d = 12


d = 4


Common difference = 4


From equation (1), we get


a = 13 - d


= 13 - 4


= 9


Thus a17 = a + 16d


= 9 + 16(4)


= 73

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