# The angles of a quadrilateral are in AP whose common difference is 10°. Find the angles.

Let these angles be x°, (x + 10)°, (x + 20)° and (x + 30)°.

Since, Sum of all angles of a quadrilateral = 360°.

x° + (x + 10)° + (x + 20)° + (x + 30)° = 360°

4x + 60° = 360°

4x = 300°

x = 75°

the angles will be 75°, 85°, 95°, 105°.

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